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The torque exerted by the display on the hinge at a particular angle is given by:

Torque = Weight x Distance from the Axis of Rotation to Center of Gravity x Cos of the Angle.

If the weight of the display is evenly distributed, the distance from the axis of rotation to the center of gravity is equal to half the length of the display. (Example shown below)

Example:
The Angle of the Display = 45°
Weight of the Display = 2 lb.
Length of the Display = 10 in.
Distance to the Center of Gravity = 5 in. (Assuming height is evenly distributed).
Hence the torque exerted by the display on the hinge at a 45° angle is:
Torque = (2 lb.)(5 in.)(Cos 45°) = 7.07 lb.in

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TorqMaster designs and manufacturers friction, torsion, and damping hinges for a variety of applications. All hinges are made in the U.S.A. by us and shipped worldwide. We offer stock, semi-custom, and full custom designs.

TorqMaster International
200 Harvard Avenue
Stamford CT 06902-6320
Tel: 203-326-5945
Fax: 203-326-5944

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